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If i is a variable of type int and p and q are variables of type pointer to int, which of the following expressions are legal?
If i is a variable and pointer variable p points to i, which of the following expressions are aliases for i?
The address of operator & returns both the address and the value of its operand.
Given the following definition statement:
char const *d = "Digipen";evaluate expression strlen(d) where function strlen is declared in C standard library header <string.h>. If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char c[] = {'D', 'i', 'g', '\0', 'i', 'p'};evaluate expression strlen(c) where function strlen is declared in C standard library header <string.h>. If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char b[] = {'D', 'i', 'g', 'i', 'p', 'e', 'n'};evaluate expression strlen(b) where function strlen is declared in C standard library header <string.h>. If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char a[] = "Digipen";evaluate expression strlen(a) where function strlen is declared in C standard library header <string.h>. If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char const *d = "Digipen";evaluate expression sizeof(d). If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char c[] = {'D', 'i', 'g', '\0', 'i', 'p'};evaluate expression sizeof(c). If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.
Given the following definition statement:
char b[] = {'D', 'i', 'g', 'i', 'p', 'e', 'n'};evaluate expression sizeof(b). If the expression cannot be compiled, write [for compile-time error]. If the expression generates undefined behavior, write [for undefined behavior]. Otherwise, write the exact value resulting from the expression's evaluation.
Brief side-note on undefined behavior: The C standard says that statements such as c = (b = a + 2) - (a = 1); and c = (b = a + 2) - (a = 1); cause undefined behavior [because we don't know whether the left or right operand of operator - is evaluated first]. When a program ventures into the realm of undefined behavior, all bets are off. The program may behave differently when compiled with different compilers. But that's not the only thing that can happen. The program may not compile in the first place, if it compiles it may not run, and if it does run, it may crash, behave erratically, or produce meaningless results. In other words, undefined behavior should be avoided like the plague.