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Computer Security (CS401)

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Given: Ciphertext = EC HEX and Sub Key K1 = 10111110 

Compute the Plaintext for S-DES one round through the following main steps as below.

 Find out O/PS of:  IP – E/P – XOR1 – Plaintext

 Hint:

- IP = 26314857

- P10 = 35274101986

- E/P = 41232341 

- P8  = 637485109

- P4  = 2431

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Given the following State Matrix of AES Cryptography Algorithm:

Question. Find out the Sub Byte State Matrix?

Hint: AES – S BOX MATRIX

Substitution Bytes in AES | Inverse Substituion Bytes in AES | SubBytes in  AES

 Choose:

         

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Given the following data of AES Cryptography Algorithm:

Plaintext in text: Two One Nine Two

Plaintext  in HEX (16 ASCII characters, 1 byte each):

 54 77  6F  20  4F  6E  65  20  4E  69  6E  65  20  54  77   6F

AES Subkey  in Hex (128 bits):  54 68 61 74 73 20 6D 79 20 4B 75 6E 67 20 46 75

AES Subkey  in Hex (128 bits):  E2 32 FC F1 91 12 91 88 B1 59 E4 E6 D6 79 A2 93

Question: Step1 Complete the computation of the State Matrix  ?

Choose:  (B)   (D)

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Given: plaintext P = M

The RSA Public Key Cryptography Algorithm: PK = {e, n} = {7, 33}

Find out the corresponding Ciphertext C = ?, using the English Index Table and the RSA Cryptography Technique.

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The number of rounds N in the Advanced Encryption Standard AES algorithm is variable and depends on some criteria such as N and size of the AES Cipher Key (bits): ___________ and __________.

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Given the following data of AES Cryptography Algorithm:

Question. Find out the Shift Rows State Matrix?

Choose:

        

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Given the following State Matrix of AES Cryptography Algorithm:

Question. Find out the Sub Byte State Matrix?

Hint: AES – S BOX MATRIX

Substitution Bytes in AES | Inverse Substituion Bytes in AES | SubBytes in  AES

 Choose:

         

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Given the following data of AES Cryptography Algorithm:

Question. Find out the Shift Rows State Matrix?

Choose:

        

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Given: S-DES Key = B9 HEX & 11 bits to make key of 10-bits.

Question: Using S-DES Key Generation Round 1 to compute the subkey K1 as below.

Find out O/PS of:  P10 - P8 - K1

Hint:

P10 = 35274101986

P8  = 637485109

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Given: ciphertext C = M

The RSA Public Key Cryptography Algorithm: Private Key = {d, n} = {3, 33}

Find out the corresponding Plaintext P = ?, using the English Index Table and the RSA Cryptography Technique.

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