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Algorithms (Dr. Dia AbuZeina)
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The time complexity of the following code is:
Giving the recurrence f( n )=2f(n-1)-f(n-2) for n>1. The root is unique which is 1. The constants c1=2 and c2=1. Therefore, the time complexity is:
What is the time complexity of the following recurrence relation?
What is the time complexity of the following recurrence relation?
What is the time complexity of the following recurrence relation?
What is the time complexity of the following?
f ( n ) = 2 f ( n / 2 ) + b n log n, where f(1)=d.
What is the time complexity of the following?
f ( n ) = 3 f ( n-1 ) - 2 f ( n - 2 ) for n≥1 f ( 0 ) = 3 and f ( 1 ) = 4.
What is the time complexity of the following?
f ( n ) = 2 f ( ) + log n
What is the time complexity of the following?
void f(int n)
{
if (n>0)
{
cout<<n;
f(n-1);
}
}
What is the time complexity of the following?
f ( n ) = f ( n-1 ) + f ( n - 2 ) , f(0)=0, f(1)=1.