Fizika i merenja 6 2024 Course Materials & Test Answers | elearning.rcub.bg.ac.rs

Veličina y se meri indirektno tako što se direktno izmere veličina x_1 sa nesigurnoašću $u_{x1}$ u_{x1} i veličina x_2 sa nesigurnošću $u_{x2}$ u_{x2} , pa se veličina y izračuna prema izrazu $y= \frac{x_1^3}{x_2}$ y= \frac{x_1^3}{x_2} . Ispravan izraz za relativnu standardnu nesigurnost merenja veličine y je

a. $\sqrt{ 3(\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}$ \sqrt{ 3(\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}

d. $\sqrt{ (\frac{u_{x1}}{x_1} )^2+3( \frac{u_{x2}}{x_2} )^2}$ \sqrt{ (\frac{u_{x1}}{x_1} )^2+3( \frac{u_{x2}}{x_2} )^2}

c. $\sqrt{ 9 (\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}$ \sqrt{ 9 (\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}

b. $\sqrt{ (\frac{u_{x1}}{x_1} )^2+9( \frac{u_{x2}}{x_2} )^2}$ \sqrt{ (\frac{u_{x1}}{x_1} )^2+9( \frac{u_{x2}}{x_2} )^2}

e. $3\sqrt{ (\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}$ 3\sqrt{ (\frac{u_{x1}}{x_1} )^2+( \frac{u_{x2}}{x_2} )^2}

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Fizika i merenja 6 2024

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