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PHS1002 Physics for Engineering - Malaysia S1 2025

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Question 4 (cont.)

(f) The direction of the induced current in the lower loop is 

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Question 4 (cont.)

When the switch in the upper loop is closed again, the current in upper loop increases quickly from zero to a constant value. While the current in the upper loop is increasing,

(d) The magnetic flux through the lower loop is 

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Question 4 (cont.)

(b) On the surface bounded by the lower loop, the direction of the magnetic field produced by the current induced in the lower loop is

0%
0%
0%
0%
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Question 4 (cont.)

(c) The direction of the induced current in the lower loop is 

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Question 4

Image failed to load

Hint for this question: see the magnetic field due to a

current loop in EM Module 3.

The upper and lower loops are horizontal in Figure 3

.

The switch in the upper loop is initially closed. When the switch is opened,

the current I in the

upper loop decreases quickly to zero. While the current in the upper loop is

decreasing,

(a)   

The magnetic flux through the lower loop is 

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Question 3 (cont.)

(c) The direction of the induced current in the loop is 

0%
0%
0%
0%
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Question 3 (cont.)

(b) On the surface bounded by the loop, the direction of the magnetic field produced by the current induced in the loop is 

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Question 3

Image failed to load

Figure 2 shows a circular conducting loop that lies in the x-y plane, where the +z axis is pointing towards you. There is a constant uniform magnetic field everywhere with direction +z. If the radius of the conducting loop increases with time,

(a) The magnetic flux through the loop is 

0%
0%
0%
0%
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Question 2 (cont.)

(c) Calculate the displacement current.

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Question 2 (cont.)

(b)  

Calculate the integral 
Image failed to load
 over the loop.

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