What will be the returned value from the following function: 

def mystery(lst):
    bingo = 0
    for i in range (0,len(lst)-1, 2):
        if lst[i] % 2 == 0 or str(lst[i]) > "4":
            bingo += 1
    return bingo

when the value of lst is [0, 1, 2, 3, 3, 5, -3, 6, 7, -4]

How many times will the marked line in the following code run when the input integer is n?

def mystery(n):
    if n <= 1:
        return 1
    else:
        return mystery(n-1) + mystery(n-2) # This line

Answer in terms of n

Consider the following implementation of a class for a Monash student: 

class Student:
    def __init__(self, name, stud_id):
        self.name = name
        self.stud_id = stud_id
    
    def __gt__(self, other):
        # TODO: Finish implementation

What will be the returned value from the following function: 

def mystery(lst):
    bongo = 0
    for item in lst:
        if item // 2 == 0 or str(item) < "2":
            bongo += 1
    return bongo

when the value of lst is [0, 1, 2, 3, 3, 5, -0, 6, 7, -8]

What is the purpose of this function? 

def enigma(my_list):
    paul = my_list[0]
    george = my_list[-1]
    for ringo in range(len(my_list)):
        if my_list[ringo] > paul:
            paul = my_list[ringo]
        elif my_list[ringo] < george:
            george = my_list[ringo]
    
    return george, paul

What is the purpose of this function? 

def mystery(my_array):
    john = 0
    jim = my_array[0]
    for jimbo in my_array:
        joe = my_array.count(jimbo)
        if joe > john:
            john = joe
            jim = jimbo
 
    return jim, john