Not a reserved word and not a keyword

A keyword but not a reserved word

A reserved word but not a keyword

A reserved word and a keyword

Static

Implicit heap dynamic

Stack dynamic

Fortran

Java

C and C++

Both Fortran and Java

Actually this is not true since "reserved word" and "keyword" are synonyms - they mean the same thing.

Smalltalk and Objective C

Ruby and Javascript

Ruby and Perl

PHP and Perl

Javascript and Objective-C

The method variables take precedence over the class level variable in this case. But the declaration inside the while loop would be ignored since Java doesn't recognize  re-declarations like this. So the println method would display the value 22.

The class level variable takes precedence in this case,  so the println method would display the value 1.

This would generate a compiler error in Java since we cannot create a variable in the while loop in baz that has the same name as a variable outside the while loop in baz.

The multiple variable declarations create "hidden" variables that hide the outer versions of the variables. So println would display the value 99

This would generate a compiler error in Java since we cannot create a variable in a local method that has the same name as a class member.

This can not compile/run since bump is nested too deeply to be accessed by thing

This can not compile/run since you can not nest let expressions inside of one another

This can not compile/run since thing is not in the same scope as the Writeline method.

This can not compile/run since you can not have two let expressions like boo and baz in the same scope

This is a perfectly valid structure for a functional language like F# and the WriteLine method would display the result of the calculation produced by invoking thing(10, 5)

Python, Ruby, Javascrpt

Java, C, Python

All of the other answers are correct

Haskell, Clojure, F#

Go, Rust, C++

Language implementation time

Compile time

Language design time.

Run time

Load time

If the language is interpreted, this would always run properly since types are determined at run-time anyway

This would not be valid syntax in any language since no types are defined

If the new language is compiled, then this can not possibly compile since no type information is available in the source code

None of the other answers is true.

Actually, all of the languages in this list would allow the use of an alias.

C

Java

Python

Perl