We added the shown PI controller to reduce the steady-state error of this system to become e_ss = 0.5 for a unit step input. Determine K_i that allows us to do that. Hint: start by finding the static position constant Kp.

Calculate Zc of the Lag Compensator so that the compensated system has a static velocity error constant  11.

Where are, approximately, the closed-loop poles when the damping ratio is: zeta=0?

Determine the angle of deficiency of the Lead Compensator to have the desired closed-loop pole at (-1 + j 5).

Note: Enter the absolute value of the answer without a sign.

In

order to change the behavior of a 2nd

order underdamped system, we need to move its closed-loop poles on the

s-plane as shown. With

this move, what happened to

We added the shown PI controller to reduce the steady-state error of this system to become e_ss = 0.25 for a unit ramp input. Determine K_i that allows us to do that. Hint: start by finding the static velocity constant Kv.

The following lead compensator is designed to obtain the desired closed-loop pole at (-2 + j 1). Determine the gain Kc of the compensator.

Find the jw-axis crossing of the root-locus of the following system. Knowing that the gain K is always positive (K>0).

The approximate angles of arrival of the root-locus from the complex zeros of the following system are:

Find the breakaway and break-in points for the following system: