What is the output of the below program

#include<stdio.h>

void main()

{

     int n;

     for (n = 9; n!=0; n--)

     printf("%d", n--);

     return 0;

}

What is the output of the below program

#include<stdio.h>

int main()

{

    int i,j,k;

    for(i=0,j=2,k=1;i<=4;i++)

   {

         printf("%d ",i+j+k);

    }

    return 0;       

}

    The subtraction of binary numbers 10111010 and 01110101 results in

Which of the following statements is not true 

1. Primary memory is directly accessible by the CPU
2. Primary memory is permanent
3. Secondary memory is permanent
4. RAM and ROM come under secondary memory

Which of the statements would compile

(i) for (i < 10; i++ ; i = 0) {}

(ii) for (i = 0; i < 10 ; i++) {}

(iii) for (i = 0; i++ ; i < 10) {}

(iv) for (i++; i = 0 ; i < 10) {}

(v) for (i++; i < 0 ; i = 10) {}

(vi) for (i < 10; i = 0 ; i++) {}

Trace the output of the below C code for n=19.99

#include <stdio.h>

int main()

{

    int n;

    if (scanf("%d", &n))

        printf("Good");

    else

        printf("Class");

    return 0;

}

    The hexadecimal number equivalent to the decimal number 499 is

Trace the output of the below C code

#include <stdio.h>

 int y;

 void main()

 {

      if (y)

          printf("Good");

      else

          printf("Class");

 }

Trace the output of the below C code

 #include<stdio.h>

void main()

{

    int num = 50;

    if (num%2=0)

    printf("Even");

    else

    printf("Odd");

}

What is the output of the below program?

int main()

{

   int i = 0;

   for (i=0; i<20; i++)

   {

     switch(i)

     {

       case 0:

         i += 5;

       case 1:

         i += 2;

       case 5:

         i += 5;

       default:

         i += 4;

         break;

     }

     printf("%d  ", i);

   }

   return 0;

}