Crowdly

Add to Chrome

Universities
moodle.nu.edu.eg
MTH112: Calculus II-2025SPRG-LECT-02

MTH112: Calculus II-2025SPRG-LECT-02

Looking for MTH112: Calculus II-2025SPRG-LECT-02 test answers and solutions? Browse our comprehensive collection of verified answers for MTH112: Calculus II-2025SPRG-LECT-02 at moodle.nu.edu.eg.

Get instant access to accurate answers and detailed explanations for your course questions. Our community-driven platform helps students succeed!

$integral fraction numerator ln left parenthesis ln x right parenthesis over denominator x space ln x end fraction d x equals integral u space d u$

What substitution did we make?

u=1/ln(x)

u=ln(ln(x))

u=ln(x)

None

u=x ln(x)

View this question

Evaluate the following integral

None

View this question

What substitution did we make?

None

View this question

Evaluate the following integral

$integral space fraction numerator open parentheses sin x minus cos x close parentheses over denominator open parentheses 1 plus cos x plus sin x close parentheses end fraction d x$

None

View this question

Evaluate the following integral

$integral fraction numerator 1 over denominator square root of x squared plus 2 x end root end fraction d x$

$sin h to the power of negative 1 end exponent open parentheses fraction numerator x plus 1 over denominator square root of 2 end fraction close parentheses plus C$

None

View this question

Evaluate the following integral

integral 2 to the power of begin display style 1 over x end style end exponent over x squared d x

$negative fraction numerator 1 over denominator ln 2 end fraction space 2 to the power of 1 over x end exponent space plus C$

$fraction numerator 1 over denominator ln 2 end fraction space 2 to the power of 1 over x end exponent space plus C$

$negative fraction numerator 1 over denominator x space ln 2 end fraction space 2 to the power of 1 over x end exponent space plus C$

None

$negative fraction numerator 1 over denominator ln 2 end fraction space 2 to the power of 1 over x squared end exponent space plus C$

View this question

Evaluate the following integral

$integral fraction numerator s e c squared x over denominator square root of 4 minus tan squared x end root end fraction d x$

$space sin to the power of negative 1 end exponent open parentheses fraction numerator tan x over denominator 2 end fraction close parentheses space plus C$

$1 half space sin to the power of negative 1 end exponent open parentheses fraction numerator tan x over denominator 2 end fraction close parentheses space plus C$

None

View this question

Evaluate the following integral

$integral space fraction numerator open parentheses sin x minus cos x close parentheses over denominator open parentheses cos x plus sin x close parentheses end fraction d x$

None

View this question

Evaluate the following integral

$integral fraction numerator sin square root of x over denominator square root of x space cos cubed open parentheses square root of x close parentheses end root end fraction d x$

$fraction numerator negative 4 over denominator square root of cos square root of x end root end fraction space plus C$

$fraction numerator 4 over denominator square root of cos square root of x end root end fraction space plus C$

None

$fraction numerator 1 over denominator square root of cos square root of x end root end fraction space plus C$

View this question

$integral fraction numerator e to the power of x over denominator 4 plus e to the power of 2 x end exponent end fraction d x$ $equals integral fraction numerator 1 over denominator 4 plus u squared end fraction space d u$

What substitution did we make?

None

View this question

Previous
1
2
3
4
5
6
Next

Want instant access to all verified answers on moodle.nu.edu.eg?

Get Unlimited Answers To Exam Questions - Install Crowdly Extension Now!

Add to Chrome

Telegram Instagram TikTok Question Bank

Terms of Use Contact Us

Add to Chrome

Add to Chrome