Course 45334

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Find the particular solution for the initial value problem.

(4x + 4)y = ; y(0) = 1

y = e^{2x2 + 4x}

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y = e^{4x2 + 4x}

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y = e^{2x2 + 4x + 1}

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y = e^{4x2 + 4x} + 1

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Find the general solution for the differential equation.

= y²(4 - e^x)

y =

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y =

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y =

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y = 4x - e^x + C

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Find the particular solution for the initial value problem.

x = 4x²e2x; y(0) = 16

y = 4xe2x - 2e2x + 18

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y = 2xe2x + 16

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y = 4xe2x - e2x + 17

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y = 2xe2x - e2x + 17

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