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Consider the following SDD:
E → E1 * E2 { E.val = E1.val * E2.val }E → id { E.val = len(id.lexeme); E.len = E.val }E → E1 + E2 { E.val = E1.len + E2.val; E.len = E.val }
For input:
a + bb * c
(len("a")=1, len("bb")=2, len("c")=1)
What will be the final value of E.val if evaluated with a correct dependency graph order?
Identify the answer for the following code:
for (i = 0; i < n; i++) { x[i] = i * 8;}
Consider the following SDD for arithmetic expressions:
E → E1 + T { E.val = E1.val + T.val }E → T { E.val = T.val }T → id { T.val = lookup(id.lexeme) }
Suppose we want to evaluate the expression a + b + c, and the symbol table contains:lookup(a)=2, lookup(b)=3, lookup(c)=5.
If evaluation order strictly follows topological ordering of the dependency graph, what is the final computed value of E?
Procedure Call TAC
y = max(a + b, c * d);
Given the SDT rules:
S → id = E { print("assign", id.lexeme, E.val) }E → E1 + T { E.val = E1.val + T.val ; print("+") }E → TT → num { T.val = num.val ; print(num.val) }
For input:
x = 3 + 4 + 5