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From ∀x P(x), we can infer P(c) using Instantiation.
A conditional statement is false only when P is and Q is __________.
The statement
"All students are smart"
can be written as .
Assume P(k): 1+2+…+k = k(k+1)/2
Then P(k+1):
In proof by contradiction, we assume the statement is .
If n=2k+1, then n is .
The statement "P and Q" is represented symbolically as .