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Vibration and noise / Vibrasie en geraas - 354

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Using the Simulink model that you created, select the damping coefficient(s) that will cause the maximum deflection of the spring in Task 1 to be less than 220 mm. There may be more than one correct answer.

Assume that m equals 9 kg, k equals 3600 N/m and x subscript 0 equals 2.5 m.

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Using the Simulink model that you created for Task 1, select the damping coefficient and initial height of the mass that produces the velocity profile shown below.

Assume that m equals 9 kg and k equals 3600 N/m.

 

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The plots (A to F) represent the response of the mass in Task 1, x left parenthesis t right parenthesis, for different damping values when m equals 9 kg, k equals 3600 N/m and x subscript 0=1.5 m.

 

Using the Simulink model that you created, select the plots that describes the response of the mass for each of the following damping values:

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Please upload your Simulink model files that you used to complete MATLAB Assignment 1.  Only upload two .slx files, one for each of the tasks in assignment.

Please name your files according to the following convention:

<task number>_<student number>.slx

e.g.: task1_12345678.slx

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As in Question 3, we are interested in the forced vibrations of a single degree of freedom.

Select the vibration response (A - J) that best matches each of the following descriptions:

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The single degree of freedom system in the figure below is subjected to forced vibrations to better understand its dynamic behaviour. 

Match one of the forced vibration responses (A - J) to each of the following forcing functions and damping values.

Assume that m equals1000 kg, k equals 49000 N/m, x subscript 0 equals 0 m and v subscript 0 equals 0 m/s.

 

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As in Question 1, assume that a mass m is connected to a wall by a spring with stiffness k and viscous damper with damping coefficient c, and slides on a surface with friction coefficient mu.

Select all the possible combinations of viscous damping and friction that will result in a response with the following characteristics:

  • The maximum positive displacement of the mass is less than 0.04 m.
  • The maximum negative displacement of the mass is less than -0.08 m (i.e. the maximum negative displacement of the mass is between -0.08 m and 0 m).
  • The mass stops oscillating before 1 s.

Assume that m equals 3 kg, k equals 300 N/m, x left parenthesis 0 right parenthesis equals x subscript 0 equals 0 m, x with. on top left parenthesis 0 right parenthesis equals v subscript 0 equals negative 1 m/s.

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Suppose that you want to understand the behaviour of the single degree of freedom system shown in the figure below.  A mass m is connected to a wall by a spring with stiffness k and a viscous damper with damping coefficient c, and slides on a surface with friction coefficient mu.

The system is subjected to some initial conditions and you want to determine the maximum positive displacement (A subscript m a x end subscript), the maximum negative displacement (A subscript m i n end subscript) and the approximate time when the mass stops oscillating (tau) - see the figure below.

Select the correct values for A subscript m a x end subscriptA subscript m i n end subscript and tau, given the following system parameters and initial conditions: m equals 3  kg, k equals 300 N/m, c equals 5 Ns/m, mu = 0.05, x left parenthesis 0 right parenthesis equals x subscript 0 equals 0.1 m, x with. on top left parenthesis 0 right parenthesis equals v subscript 0 equals 1 m/s. Assume g equals 9.81 m/s2.

 

 

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Which diagram(s) describe the following system's mode shapes?

open square brackets table row cell 2.25 end cell 0 row 0 cell 6.75 end cell end table close square brackets open parentheses table row cell theta with.. on top subscript 1 end cell row cell theta with.. on top subscript 2 end cell end table close parentheses plus open square brackets table row 225 cell negative 225 end cell row cell negative 225 end cell 225 end table close square brackets open parentheses table row cell theta subscript 1 end cell row cell theta subscript 2 end cell end table close parentheses equals open parentheses table row 0 row 0 end table close parentheses

Watter diagram(me) beskryf die onderstaande sisteem se modevorms?

open square brackets table row cell 2.25 end cell 0 row 0 cell 6.75 end cell end table close square brackets open parentheses table row cell theta with.. on top subscript 1 end cell row cell theta with.. on top subscript 2 end cell end table close parentheses plus open square brackets table row 225 cell negative 225 end cell row cell negative 225 end cell 225 end table close square brackets open parentheses table row cell theta subscript 1 end cell row cell theta subscript 2 end cell end table close parentheses equals open parentheses table row 0 row 0 end table close parentheses

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