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With the aid of the substitutions e^x=\tan \theta and \cosh x=\frac {1}{2}...

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With the aid of the substitutions e^x=\tan \theta e^x=\tan \theta and \cosh x=\frac {1}{2}\left (e^x+e^{-x}\right )\cosh x=\frac {1}{2}\left (e^x+e^{-x}\right ), evaluate the integral \displaystyle \int{sech} x \,dx\displaystyle \int{sech} x \,dx.

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