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Привести до випередженої нормальної форми формулу \forall x \overline{ \exists y (P(x)\to Q(y))}
\forall x \forall y(P(x)\vee \overline{Q}(y))
\exists x \exists y( \overline{P}(x)\vee Q(y))
\forall x \forall y(P(x)\wedge \overline{Q}(y))
\exists x \forall y(\overline{P}(x)\vee Q(y))
\forall x \exists y(P(x)\vee \overline{Q}(y))
\forall x \exists y(P(x)\wedge \overline{Q}(y))
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