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What is the result of executing MOV A, #9AH followed by ANL A, #0FH?

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What is the result of executing MOV A, #9AH followed by ANL A, #0FH?

0x0A, because ANL performs bitwise AND, preserving only the lower nibble (9AH = 1001 1010, 0FH = 0000 1111, AND = 0000 1010 = 0AH)

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0x9A, unchanged because AND doesn't modify the accumulator

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0x90, by clearing the lower nibble to all 0s

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0x9F, by setting the lower nibble bits to all 1s

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