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What is the result of executing MOV A, #0AAH followed by XRL A, #0FFH?
0x55, because XRL performs bitwise XOR where each bit is inverted (AAH = 1010 1010, FFH = 1111 1111, XOR = 0101 0101 = 55H)
0xAA, unchanged because XOR with all 1s preserves the original value
0xFF, by setting all bits to 1 through the XOR operation
0x00, by clearing all bits through exclusive OR
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