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What axiom shows the product rule form?
P(a ∧ b) = P(a ∧ b)P(b)
P(a ∧ b) = P(a ∨ b)P(b)
(a ∨ b) = P(a | b)P(b)
P(a ∧ b) = P(a | b)P(b)
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