logo

Crowdly

Izan bedi funtzioa. Hurbil ezazu  -ren balioa puntuko gainazalarekiko ...

✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.

Izan bedi f left parenthesis x comma y right parenthesis equals fraction numerator 1 over denominator square root of x cubed plus y squared plus cos open parentheses x space y close parentheses end root end fraction funtzioa. Hurbil ezazu f left parenthesis negative 0.5 comma 0.5 right parenthesis-ren balioa P left parenthesis negative 1 comma 0 right parenthesis puntuko z equals f left parenthesis x comma y right parenthesis gainazalarekiko plano ukitzailea erabiliz (diferentzialaren bidezko hurbilketa). Zein da hurbilketan egindako errore absolutua?

Laguntza: f left parenthesis x comma y right parenthesis funtzioaren P left parenthesis a comma b right parenthesis puntuko plano ukitzailearen ekuazio ondorengoa da

z equals f left parenthesis a comma b right parenthesis plus f subscript x left parenthesis a comma b right parenthesis left parenthesis x minus a right parenthesis plus f subscript y left parenthesis a comma b right parenthesis left parenthesis y minus b right parenthesis

----------------------------------------------------

Sea la función  f left parenthesis x comma y right parenthesis equals fraction numerator 1 over denominator square root of x cubed plus y squared plus cos open parentheses x space y close parentheses end root end fraction. Aproximar el valor de f left parenthesis negative 0.5 comma 0.5 right parenthesis utilizando el plano tangente a la superficie z equals f left parenthesis x comma y right parenthesis en el punto P left parenthesis negative 1 comma 0 right parenthesis. ¿Cuál es el error absoluto cometido en dicha aproximación?

Ayuda: la ecuación del plano tangente a la superficie z equals f left parenthesis x comma y right parenthesis en el punto P left parenthesis a comma b right parenthesis es la siguiente:

z equals f left parenthesis a comma b right parenthesis plus f subscript x left parenthesis a comma b right parenthesis left parenthesis x minus a right parenthesis plus f subscript y left parenthesis a comma b right parenthesis left parenthesis y minus b right parenthesis

0%
0%
0%
0%
More questions like this

Want instant access to all verified answers on egela.ehu.eus?

Get Unlimited Answers To Exam Questions - Install Crowdly Extension Now!