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After executing the following sequence, what is the final value in A? MOV A, #55H, ANL A, #0FH, SWAP A
0x05, because SWAP has no effect after the masking operation
0x50, because ANL extracts lower nibble (55H AND 0FH = 05H), then SWAP moves it to upper nibble (05H → 50H)
0xA5, by inverting the bits during the swap operation
0x50, because SWAP multiplies the value by 16 in hex notation
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