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Consider the following code: for (int i = 0; i < 100; i++) { x = 10 *...
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Consider the following code:
for (int i = 0; i < 100; i++) {
x = 10 * 20;
}
After optimisation:
x = 10 * 20;
for (int i = 0; i < 100; i++) {
// no multiplication inside loop
}
If one multiplication takes 2 units of time, how
much time is saved?
0%
0%
100%
0%