For the combustion of sucrose: C 12 H 22 O 11 + 12O 2 ---> 12CO 2 + 11H 2 O...
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For the combustion of sucrose:
C12H22O11 + 12O2 ---> 12CO2 + 11H2O
there are 10.0 g of sucrose and 10.0 g of oxygen reacting. Which is the limiting reagent? You may use decimals or whole number atomic weights. Your answer must be symbols . No space like H2O
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