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What is the molarity of Fe(NO3)3 in a 2.14% w/v Fe(NO3)3 solution? (Molar Mass of Fe(NO3)3 = 241.88).
Hint: X % w/v = Xg/100mL = X x 10 g /L
Molarity = moles / L so divide X x 10 g by molar mass will give you moles per liter (M).