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A pendulum is modelled as shown below. Regard the rod as massless, with a concen...

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A pendulum is modelled as shown below. Regard the rod as massless, with a concentrated mass, m, at the end. Assume that a and L refer to the indicated lengths and that mck subscript 1 and k subscript 2 respectively refer to the mass, damping and stiffness coefficients in SI units. The springs are unstretched when the rod is vertical (θ = 0). Take clockwise moments as positive. Assume that the pendulum moves through small angles and that g equals 9.81 space straight m divided by straight s squared.

The equation of motion for the pendulum can be written in the following form:

A theta with.. on top plus B theta with. on top plus C theta equals 0

Given the following values, calculate the value of A.

 m equals4.5 kgc equals13.1 straight N. straight s divided by straight mk subscript 1 equals2.7 straight N divided by straight mk subscript 2 equals2.9 straight N divided by straight ma equals0.3 straight m, and L equals1.2 straight m.

Provide your answer to two (2) decimal places and do not use any units in your final answer. Example: 2.099145... [m] should be entered as 2.10. Do not simplify the equation of motion by dividing by constants, for example: do not divide by length L.

 

 

‘n Pendulum kan in die model hieronder voorgestel word. Beskou die stang as ‘n masselose staaf met ‘n gekonstreerde massa, mop die eindpunt. Neem aan dat a en L verwys na die aangeduide lengte en dat mck subscript 1 en k subscript 2 verwys na die mass, demping, en styfheid koëffisiënte in SI eenhede. Die vere is ongestrek as die staaf vertikaal is (θ = 0)Neem oomblikke met die kloksgewys as positief. Neem aan die pendulum beweeg slegs deur klein hoeke en dat g equals 9.81 space straight m divided by straight s squared.

Die bewegingsvergelyking van die pendulum kan in die volgende vorm geskryf word:

A theta with.. on top plus B theta with. on top plus C theta equals 0

Gebruik die gegewe waardes om die waarde van A te bepaal.

 m equals4.5 kgc equals13.1 straight N. straight s divided by straight mk subscript 1 equals2.7 straight N divided by straight mk subscript 2 equals2.9 straight N divided by straight ma equals0.3 straight m, en L equals1.2 straight m.

Gebruik twee (2) desimale in die finale antwoord. Moet nie eenhede gebruik in die antwoord nie. Voorbeeld: 2.099145... [m] moet as 2.10 ingeskryf word. Vereenvoudig nie die bewegingsvergelyking deur te deel deur konstantes nie, byvoorbeeld: verdeel nie met lengte L nie.

      

 

 

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