Givet den balanserade reaktionen: 3 Fe 3+ (aq) + Al(s) -> 3 Fe 2+ (aq) + Al 3+ (aq) Hur många mol elektroner avges av 1 mol Al(s)?

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Givet den balanserade reaktionen: 3 Fe³⁺(aq) + Al(s) -> 3 Fe²⁺(aq) + Al³⁺(aq)

Hur många mol elektroner avges av 1 mol Al(s)?

1 mol

9 mol

6 mol

3 mol

100%

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