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Put the steps in the correct order to prove that m+p is even if m+n and n+p is e...

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Put the steps in the correct order to prove that m+p is even if m+n and n+p is even.

m+n is even , the m+n=2k and n+p is even then n+p = 2k' where k and k' are integers.

Subtract 2n from both sides and factorize to obtain m+p=2(k+k'-n)

add the two equations, we obtain m+p+2n=2k+2k'

then m+p=2k" where k"=k+k'-n is an integer

we conclude that m+p is even

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