The following diagram shows a mass of m kg, undergoing tension forces T 1 and T 2 (N) from two cables. The mass is attached to the floor via a spring that has a spring constant k (N/m), which is undergoing a displacement of D (m).

What are the equations of motion in the x and y directions (respectively)? Note: a x and a y are the acceleration in ms -2 in x and y directions, respectively.

Question

The following diagram shows a mass of m kg, undergoing tension forces T 1  and T 2  (N) from two cables. The mass is attached to the floor via a spring that has a spring constant k (N/m), which is undergoing a displacement of D (m). 
  
 What are the equations of motion in the x and y directions (respectively)? Note: a x  and a y   are the acceleration in ms -2  in x and y directions, respectively.

Answer

ma x  = -T 2  sin θ 2  + T 1  sin θ 1   
 ma y  = T 2  cos θ 2  + T 1  cos θ 1  - mg - kD

Answer

ma x  = -T 2  cos θ 2  + T 1  cos θ 1   
 ma y  = T 2  sin θ 2  + T 1  sin θ 1  - mg + kD

Answer

ma x  = -T 2  sin θ 2  + T 1  sin θ 1   
 ma y  = T 2  cos θ 2  + T 1  cos θ 1  - mg + kD

Answer

ma x  = -T 2  cos θ 2  + T 1  cos θ 1   
 ma y  = T 2  sin θ 2  + T 1  sin θ 1  - mg - kD

Answer

ma x  = T 2  sin θ 2  - T 1  sin θ 1   
 ma y  = T 2  cos θ 2  + T 1  cos θ 1  - mg - kD

Answer

ma x  = T 2  cos θ 2  - T 1  cos θ 1   
 ma y  = T 2  sin θ 2  + T 1  sin θ 1  - mg + kD

Answer

ma x  = T 2  cos θ 2  - T 1  cos θ 1   
 ma y  = T 2  sin θ 2  + T 1  sin θ 1  - mg - kD

Answer

ma x  = T 2  sin θ 2  - T 1  sin θ 1   
 ma y  = T 2  cos θ 2  + T 1  cos θ 1  - mg + kD

Crowdly

The following diagram shows a mass of m kg, undergoing tension forces T 1 and T...

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