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Given the following NFA \epsilon -closure ( \{ 3, 8 \} ) is equal to

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Given the following NFA

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$\epsilon -closure ( \{ 3, 8 \} )$ \epsilon -closure ( \{ 3, 8 \} ) is equal to

$\{1, 2, 3, 5, 7, 8 \}$ \{1, 2, 3, 5, 7, 8 \}

$\{3, 6, 7, 8 \}$ \{3, 6, 7, 8 \}

$\{1, 2, 3, 4, 6, 7, 8 \}$ \{1, 2, 3, 4, 6, 7, 8 \}

$\{ 1, 2, 4, 6, 7 \}$ \{ 1, 2, 4, 6, 7 \}

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