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Для заданої функції f(x)=4х3+6х знайти первісну графік якої проходить через точку В(-1;2).
F(x)=x4+3x+2
F(x)=4x4+6x2-2
F(x)=x4+3x2-2
F(x)=x3+6x-2
F(x)=12x2+6x+6
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