Suppose you wrap a component as follows: Component c = new DecoratorA(new DecoratorB(new ConcreteComponent())). In what order are the decorators typically evaluated when c.operation() is called?

Question

Answer

DecoratorA receives the call first, delegating to DecoratorB, which delegates to ConcreteComponent.

Answer

Execution order is non-deterministic and depends on thread scheduling.

Answer

DecoratorB executes first, then DecoratorA, then ConcreteComponent.

Answer

ConcreteComponent must always execute before any decorator starts.

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Suppose you wrap a component as follows: Component c = new DecoratorA(new Decora...

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