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у VBA визначити правильний запис виразу z=x12-5,8ln3x, якщо x >0.
z = x^12-5.8*ln(3*x)/ln(10);
z := exp(12*ln(x))-5.8*lg(3*x);
z = x^12-5.8*log(3*x);
z = exp(12*ln(x))-5.8*ln(3*x);
z:= exp(12*ln(x))-5.8*ln(3x);
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