Let S be a string of length n . In 1-based indexing, if Z[k] > 0 , for 2\le k \le n then S[k\dots k+Z[k] - 1] = S[1\dots Z[k]] .

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Let S be a string of length n . In 1-based indexing, if Z[k] > 0 , ...

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Let S be a string of length n . In 1-based indexing, if Z[k] > 0 , for $2\le k \le n$ 2\le k \le n then $S[k\dots k+Z[k] - 1] = S[1\dots Z[k]]$ S[k\dots k+Z[k] - 1] = S[1\dots Z[k]].

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