A numerical method has an error of order \mathcal {O}(h^3) . If the step size is reduced from h to h/2 , approximately what happens to the error?

Question

A numerical method has an error of order   \mathcal {O}(h^3) . If the step size is reduced from   h  to   h/2 , approximately what happens to the error?

Answer

It is reduced by a factor of   16

Answer

It is reduced by a factor of   8

Answer

It is reduced by a factor of   2

Answer

None

Answer

It is reduced by a factor of   4

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A numerical method has an error of order \mathcal {O}(h^3) . If the step size ...

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