Určete Taylorův polynom druhého stupně funkce
f(x)=\cos(3x-\frac{\pi}{4})+3. se středem v bodě a=\frac{\pi}{3} .

Question

Určete Taylorův polynom druhého stupně funkce
  f(x)=\cos(3x-\frac{\pi}{4})+3.  se středem v bodě   a=\frac{\pi}{3} .

Accepted Answer

3-\frac{\sqrt 2}{2}-\frac{3\sqrt 2}{2}(x-\frac{\pi}{3})+\frac{9\sqrt 2}{4}(x-\frac{\pi}{3})^2

Answer

3-\frac{\sqrt 2}{2}-\frac{3\sqrt 2}{2}(x+\frac{\pi}{3})-\frac{9\sqrt 2}{2}(x+\frac{\pi}{3})^2

Answer

3-\frac{\sqrt 2}{2}-\frac{3\sqrt 2}{2}(x-\frac{\pi}{3})+\frac{9\sqrt 2}{2}(x-\frac{\pi}{3})^2

Answer

3-\frac{\sqrt 2}{2}-\frac{3\sqrt 2}{2}(x-\frac{\pi}{3})-\frac{9\sqrt 2}{2}(x-\frac{\pi}{3})^2

Answer

3-\frac{\sqrt 2}{2}-\frac{3\sqrt 2}{2}(x-\frac{\pi}{3})-\frac{9\sqrt 2}{4}(x-\frac{\pi}{3})^2

Answer

3-\frac{\sqrt 2}{2}-\frac{\sqrt 2}{2}(x-\frac{\pi}{3})-\frac{\sqrt 2}{4}(x-\frac{\pi}{3})^2

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