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If y=x^{\cos\,x} then find \dfrac{dy}{dx} .

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If $y=x^{\cos\,x}$ y=x^{\cos\,x} then find $\dfrac{dy}{dx}$ \dfrac{dy}{dx}.

$x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\sin\,x\,\text{ln}\,x$ x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\sin\,x\,\text{ln}\,x

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$x^{\cos\,x-1}\cos\,x+x^{\cos\,x}\text{ln}\,x$ x^{\cos\,x-1}\cos\,x+x^{\cos\,x}\text{ln}\,x

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$x^{\cos\,x-1}\cos\,x$ x^{\cos\,x-1}\cos\,x

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$x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\,\sin\,x$ x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\,\sin\,x

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$x^{\cos\,x}\text{ln}(\cos\,x)$ x^{\cos\,x}\text{ln}(\cos\,x)

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