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The residue of f(z)= \frac{1}{(z^2+1)^2} about the pole z=i is

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The residue of $f(z)= \frac{1}{(z^2+1)^2}$ f(z)= \frac{1}{(z^2+1)^2} about the pole z=i is

$-\frac{i}{4}$ -\frac{i}{4}

$-\frac{i}{2}$ -\frac{i}{2}

$\frac{i}{4}$ \frac{i}{4}

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