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Фруктоза може давати реакцію «срібного дзеркала» тому, що (OH–CH₂–CH(OH)–CH(OH)–...

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Фруктоза може давати реакцію «срібного дзеркала» тому, що (OH–CH₂–CH(OH)–CH(OH)–CH(OH)–C(O)–CH₂–OH↔OH–CH₂–CH(OH)–CH(OH)–CH(OH)–C(OH)=CH–OH↔OH–CH₂–CH(OH)–CH(OH)–CH(OH)–CH(OH)–COH):
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