Pole powierzchni obszaru D B = {( r , ) ∈ R 2 : ( r ≤ 6 ) ∧ ( - 3 π / 2 ≤ ≤ π / 2 ) } wynosi :

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Pole powierzchni obszaru

D _B = {( r , ) ∈ R ²: ( r ≤ 6 ) ∧ ( - 3 π / 2 ≤ ≤ π / 2 ) }

wynosi :

12 π

9 π

18 π

36 π

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