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After executing MOV A, #0C5H followed by SWAP A, what is the value in the accumulator?
0xC5, unchanged because SWAP requires two operands
0xE7, by performing arithmetic on the nibbles
0x3A, by inverting bits during the swap operation
0x5C, because SWAP exchanges the upper nibble (C) with the lower nibble (5), resulting in 0101 1100
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