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Яка формула лежить в основі методу Ньютона?
xₖ₊₁ = xₖ - f(xₖ)/f'(xₖ)
xₖ₊₁ = (a+b)/2
xₖ₊₁ = xₖ₋₁ - f(xₖ₋₁)
xₖ₊₁ = f(xₖ)/f''(xₖ)
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