Dans le cas d’un solide 1 en translation pure, la puissance des forces extérieur...

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Dans le cas d’un solide 1 en translation pure, la puissance des forces extérieures devient :

P (ext \to 1, \mathcal{R}_g ) = \overrightarrow{F}(ext \to 1) \cdot \overrightarrow{V}(G / \mathcal{R}_g)

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P (ext \to 1, \mathcal{R}_g ) = \overrightarrow{M}( O; ext \to 1) \cdot \overrightarrow{\Omega}( 1 / \mathcal{R}_g)

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P (ext \to 1, \mathcal{R}_g ) = \overrightarrow{F}(ext \to 1) \cdot \overrightarrow{V}(A; 1 / \mathcal{R}_g)

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P (ext \to 1, \mathcal{R}_g ) = 0

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