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Adott egy 5 változós függvény, ahol a kimenet akkor 1-es, ha az E és az A változó 0 értékű. Adja meg a függyvény igazságtábláját az alábbi formátumban:
| Sorszám | E | D | C | B | A | Y |
| 0 | 0 | 0 | 0 | 0 | 0 | |
| 1 | 0 | 0 | 0 | 0 | 1 | |
| 2 | 0 | 0 | 0 | 1 | 0 | |
| 3 | 0 | 0 | 0 | 1 | 1 | |
| 4 | 0 | 0 | 1 | 0 | 0 | |
| 5 | 0 | 0 | 1 | 0 | 1 | |
| 6 | 0 | 0 | 1 | 1 | 0 | |
| 7 | 0 | 0 | 1 | 1 | 1 | |
| 8 | 0 | 1 | 0 | 0 | 0 | |
| 9 | 0 | 1 | 0 | 0 | 1 | |
| 10 | 0 | 1 | 0 | 1 | 0 | |
| 11 | 0 | 1 | 0 | 1 | 1 | |
| 12 | 0 | 1 | 1 | 0 | 0 | |
| 13 | 0 | 1 | 1 | 0 | 1 | |
| 14 | 0 | 1 | 1 | 1 | 0 | |
| 15 | 0 | 1 | 1 | 1 | 1 | |
| 16 | 1 | 0 | 0 | 0 | 0 | |
| 17 | 1 | 0 | 0 | 0 | 1 | |
| 18 | 1 | 0 | 0 | 1 | 0 | |
| 19 | 1 | 0 | 0 | 1 | 1 | |
| 20 | 1 | 0 | 1 | 0 | 0 | |
| 21 | 1 | 0 | 1 | 0 | 1 | |
| 22 | 1 | 0 | 1 | 1 | 0 | |
| 23 | 1 | 0 | 1 | 1 | 1 | |
| 24 | 1 | 1 | 0 | 0 | 0 | |
| 25 | 1 | 1 | 0 | 0 | 1 | |
| 26 | 1 | 1 | 0 | 1 | 0 | |
| 27 | 1 | 1 | 0 | 1 | 1 | |
| 28 | 1 | 1 | 1 | 0 | 0 | |
| 29 | 1 | 1 | 1 | 0 | 1 | |
| 30 | 1 | 1 | 1 | 1 | 0 | |
| 31 | 1 | 1 | 1 | 1 | 1 |