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Given formula ψ := (x) ∧ (¬y ∨ ¬z) ∧ (¬x ∨ y ∨ z)
(¬y ∨ ¬z) is a literal.
(¬x ∨ y ∨ z) is a conjunction of three literals.
y is a literal.
ψ is a disjunction of clauses.
¬y is a literal.
(¬x ∨ y ∨ z) is a clause of size three.
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