What output will the following code produce?

n = 10

while n != 1:

print (n,end=' ')

if n % 2 == 0: # n is even

n = n // 2

else: # n is odd

n = n * 3 + 1

Question

What output will the following code produce?

n = 10 
 
while n != 1: 
 
    print (n,end=' ') 
 
    if n % 2 == 0:        # n is even 
 
        n = n // 2 
 
    else:                 # n is odd 
 
        n = n * 3 + 1

Accepted Answer

10 5 16 8 4 2

Answer

9 28 14 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2

Answer

None an error will be displayed

Answer

8 4 2

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What output will the following code produce? n = 10 while n != 1: ...

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