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Jeżeli α \alpha jest kątem ostrym i t g α = 2 tg \alpha=2 , to:

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Jeżeli α \alpha jest kątem ostrym i tgα=2 tg \alpha=2 , to:

a. \( sin \alpha= \frac{2 \sqrt{5} }{5} \)

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b. \( sin \alpha= \frac{\sqrt{ 5}}{5} \)

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c. \( sin \alpha= \sqrt{5} \)

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d. \( sin \alpha= \frac{\sqrt{5}}{ 2} \)

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