Considere o AP M=({p,q,r},{a,b,c,d}, {a,b,c,d,W,S,T,R,Z 0 }, p, Z 0 , {r}, d ) Qual das seguintes sequências de movimentos justifica que abcda Î L(M) ?

Question

Considere o AP M=({p,q,r},{a,b,c,d}, {a,b,c,d,W,S,T,R,Z 0 }, p, Z 0 , {r},  d )   Qual das seguintes sequências de movimentos  justifica que abcda Î L(M) ?

Accepted Answer

(p, abcda , Z 0 ) ├ M (q, abcda ,W Z 0 ) ├ M (q, abcda , SRZ 0 ) ├ M (q,  abcda , aSdRZ 0 ) ├ M (q, bcda , SdRZ 0 ) ├ M (q, bcda , TdRZ 0 ) ├ M (q, bcda ,b TcdRZ 0 ) ├ M (q, cda , TcdRZ 0 ) ├ M (q, cda , cdRZ 0 ) ├ M (q, da , dRZ 0 ) ├ M (q, a , RZ 0 ) ├ M (q, a ,a RZ 0 ) ├ M (q, L , RZ 0 ) ├ M (q, L , Z 0 ) ├ M (r,  L , Z 0 )

Answer

(p, abcda , Z 0 ) ├ M (q, abcda ,W Z 0 ) ├ M (q, abcda , SRZ 0 ) ├ M (q,  abcda , aSdRZ 0 ) ├ M (q,a bcda ,a TdRZ 0 ) ├ M (q,a bcda ,ab TcdRZ 0 ) ├ M (q,a bcda ,ab cdRZ 0 ) ├ M (q,a bcda ,ab cdaRZ 0 ) ├ M (q,a bcda ,ab cdaZ 0 ) ├ M (q, bcda ,b cdaZ 0 ) ├ M (q, cda , cdaZ 0 ) ├ M (q, da , daZ 0 ) ├ M (q, a , aZ 0 ) ├ M (q, L , Z 0 ) ├ M (q, L , L )

Answer

(p, abcda , Z 0 ) ├ M (q, abcda ,W Z 0 ) ├ M (q, abcda , SRZ 0 ) ├ M (q,  abcda , aSdRZ 0 ) ├ M (q, bcda , SdRZ 0 ) ├ M (q, bcda , TdRZ 0 ) ├ M (q, bcda ,b TcdRZ 0 ) ├ M (q, cda , TcdRZ 0 ) ├ M (q, cda , cdRZ 0 ) ├ M (q, da , dRZ 0 ) ├ M (q, a , RZ 0 ) ├ M (q, a ,a RZ 0 ) ├ M (q, L , RZ 0 ) ├ M (q, L , Z 0 ) ├ M (q,  L ,  L )

Answer

(p, abcda , Z 0 ) ├ M (q, abcda ,W Z 0 ) ├ M (q, abcda , SRZ 0 ) ├ M (q,  abcda , aSdRZ 0 ) ├ M (q,a bcda ,a TdRZ 0 ) ├ M (q,a bcda ,ab TcdRZ 0 ) ├ M (q,a bcda ,ab cdRZ 0 ) ├ M (q,a bcda ,ab cdaRZ 0 ) ├ M (q,a bcda ,ab cdaZ 0 ) ├ M (q, bcda ,b cdaZ 0 ) ├ M (q, cda , cdaZ 0 ) ├ M (q, da , daZ 0 ) ├ M (q, a , aZ 0 ) ├ M (q, L , Z 0 ) ├ M (r, L , Z 0 )

(q,a,X)	d (q,a,X)
(p, L, Z₀)	{(q,WZ₀)}
(q, L, Z₀)	{(r,Z₀),(q,L)}
(q, L, W)	{(q,SR)}
(q, L, T)	{(q,bTc), (q,L)}
(q, L, S)	{(q,aSd), (q,T)}
(q, L, R)	{(q,aR), (q,L)}
(q,a,a)	{(q,L)}
(q,b,b)	{(q,L)}
(q,c,c)	{(q,L)}
(q,d,d)	{(q,L)}
…	Æ

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Considere o AP M=({p,q,r},{a,b,c,d}, {a,b,c,d,W,S,T,R,Z 0 }, p, Z 0 , {r}, d ) ...

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