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Нехай в додатку servletapp визначено сервлет Exam_servlet: import java.io.Prin...

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Нехай в додатку servletapp визначено сервлет Exam_servlet:

import java.io.PrintWriter;

import java.io.IOException;

import javax.servlet.ServletException;

import javax.servlet.annotation.WebServlet;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

 

@WebServlet("/example")

public class HelloServlet extends HttpServlet {

    protected void doGet(HttpServletRequest request, HttpServletResponse response)

            throws ServletException, IOException {

        response.setContentType("text/html");

        PrintWriter writer = response.getWriter();

        String name = request.getParameter("subject");

        String age = request.getParameter("rating");

        try {

            writer.println("<h2>Subject: " + subject + "; Rating: " + rating + "</h2>");

        } finally {

            writer.close(); 

        }

    }

}

Як можна передати значення Java та 95 відповідних параметрів subject та rating сервлету через адресний рядок?

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