A Newton-Raphson iteration reaches a point x_k for which f'(x_k)=0 . What immediate difficulty does this create?

Question

A Newton-Raphson iteration reaches a point   x_k  for which   f'(x_k)=0 . What immediate difficulty does this create?

Accepted Answer

The Newton iteration cannot be evaluated in its usual form

Answer

The function becomes discontinuous

Answer

The method automatically becomes the Secant method

Answer

None

Answer

The root becomes multiple automatically

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