Розрахуйте константу рівноваги реакції: [Ru(NH 3 ) 6 ] 2+ + [IrBr 6 ] 2- = [Ru(NH 3 ) 6 ] 3+ + [IrBr 6 ] 3- [Ru(NH 3 ) 6 ] 3+ + e ↔ [Ru(NH 3 ) 6 ] 2+ , φ 0 = 0,05 B [IrBr 6 ] 2- + e ↔ [IrBr 6 ] 3- , φ 0 = 0,95 B (F/2,3RT = 1/0,059)

Crowdly

Add to Chrome

✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.

Розрахуйте константу рівноваги реакції:

[Ru(NH₃)₆]²⁺ + [IrBr₆]^2- = [Ru(NH₃)₆]³⁺ + [IrBr₆]^3-

[Ru(NH₃)₆]³⁺ + e ↔ [Ru(NH₃)₆]²⁺, φ⁰ = 0,05 B

[IrBr₆]^2- + e ↔ [IrBr₆]^3-, φ⁰ = 0,95 B

(F/2,3RT = 1/0,059)

15,25

1,78 × 10¹⁵

100%

2,63 × 10⁵

7,15 × 10¹²

Get Unlimited Answers To Exam Questions - Install Crowdly Extension Now!

Add to Chrome